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8v^2-15=v
We move all terms to the left:
8v^2-15-(v)=0
We add all the numbers together, and all the variables
8v^2-1v-15=0
a = 8; b = -1; c = -15;
Δ = b2-4ac
Δ = -12-4·8·(-15)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{481}}{2*8}=\frac{1-\sqrt{481}}{16} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{481}}{2*8}=\frac{1+\sqrt{481}}{16} $
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